[Israel.pm] Using variables

bc.other bc.other at gmail.com
Tue Jan 6 08:25:19 PST 2009


OK, I will explain

I got 2 variables: $var1 = 100 and $var2 = 200
And I got another variable $digit = 1

I need a way to print $var1 using $digit and string "var"
I tried ${"var" . $digit} but it didn't work for me,
I tried $var{$digit} - but it will try look for hash value - nnoooo
I tried $var${digit} - but it's an error mistake....:-(

The reason I need it, because I need to loop on different variables (same
name, different digits)
and check their value against something....and I wanted to do that using a
for/while loop...

Thanks
Chanan

-----Original Message-----
From: perl-bounces at perl.org.il [mailto:perl-bounces at perl.org.il] On Behalf
Of Gabor Szabo
Sent: Tuesday, January 06, 2009 5:55 PM
To: Perl in Israel
Subject: Re: [Israel.pm] Using variables

On Tue, Jan 6, 2009 at 5:33 PM, Chanan Berler <chananb at centerity.com> wrote:
> Hello All,
>
> I have the following prog:
>
> my $digit = 1;
> my $var1 = 100;
> my $var2 = 200;
>
> And I need to print $var1, $var2 - but using the $digit concatenated with
> the word 'var'.
> Can anyone help me? Suppose to be an easy task - but I got a blackout
..wow

I did not understand. Could you show us what would be the expected
output int the
case you showed us?

Gabor
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